- For question 1d. in Homework 12, one possible solution Mr. Marchetti showed us was the function
Unfortunately, the graphing method only gives approximations so it is better used as a way to check your answers.
6. We also solved this problem graphically in class to find intersections at x=2 and x=-7
If this problem were an inequality like this , the solution would be x<-7 Then we learned how to solve a problem algebraically: 2. To solve this problem, both sides have to be multiplied by (x-4) to eliminate the fraction
So then the equation looks like:
To finish solving, bring the 5x to one side and the 3 to the other:
-4x=-23 Then divide both sides by -4 so
10. The first step would be to factor wherever possible, so the new equation would be:
The next step would be to multiply each side by (x+4)(x-1)
After distribution, all like terms are gathered.
Since this equation is quadratic, 15 can be subtracted from both sides to make one side zero and the other side can be factored and solved from there.
To make one of the sides zero so the equation will be equal to zero,
or
The first answer to this problem is not relevant unfortunately, because the x=1 in the second fraction would be:
Which doesn't make sense because it is not possible to divide by zero. This problem can be checked by graphing the system which shows that at x=1, there is a vertical asymptote so it is not a possible anyswer, which is called an extraneous solution.
Homework:
- Worksheet page 380 choose 2 problems from Section Exercises 5.4 from questions 1-8 and choose 3 problems from questions 9-19. Solve each algebraically and then check them graphically.
- PoW 8 due any day from Thursday to Tuesday
- There is a quiz over functions on Thursday 10/9
The next scribe will be Maddy.